A particle does uniform circular motion in a horizontal plane. The radius of the circle is 20 cm. The centripetal force acting on the particle is 10 N. It’s kinetic energy is
Practice this Circular Motion question from Engineering Entrance Exam.
Question Details
Physics
Circular Motion
Engineering Entrance Exam
Question
A particle does uniform circular motion in a horizontal plane. The radius of the circle is 20 cm. The centripetal force acting on the particle is 10 N. It’s kinetic energy is
Solution
\(\frac{{m{v^2}}}{r} = 10N\) (given)
\( \Rightarrow m{v^2} = 10 \times r\) \( = 10 \times 0.2 = 2\)
Kinetic energy \(\frac{1}{2}m{v^2} = \frac{1}{2}(2) = 1J\)