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A projectile is fired with velocity \(u\) making angle \(\theta\) with the horizontal. What is the change in velocity when it is at the highest point

Practice this Projectile Motion question from Engineering Entrance Exam.

Question Details

Easy
Physics Projectile Motion Engineering Entrance Exam
Question

A projectile is fired with velocity \(u\) making angle \(\theta\) with the horizontal. What is the change in velocity when it is at the highest point

Options
A

\(u\cos \theta \)

B

\(u\)

C

\(u\sin \theta \)

Correct
D

\(u\cos \theta -u\)

Solution

Since horizontal component of velocity remain always constant therefore only vertical component of velocity changes.

Initially vertical component \(u\sin \theta \)

Finally it becomes zero. So change in velocity \(=u\sin \theta \)

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